find the value of k if x² + kx +6=(x+2)
(x+3)
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Answer:
x²+kx+6=(x+2)(x+3)
x²+kx+6=x²+2x+3x+6
x²+kx+6=x²+5x+6
On comparing LHS with RHS, we get
kx=5x
k=5
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