Question

find the value of k if: xy²k=(4xy+3y)² -(4xy-3y)²​

Answer 1

Answer:

$x {y}^{2} k = {(4xy + 3y)}^{2} - {(4xy - 3y)}^{2} \\ x {y}^{2} k = (4xy + 3y - 4xy + 3y)(4xy + 3y + 4xy - 3y) \\ x {y}^{2} k = 6y \times 8xy \\ = 48x {y}^{2} \\ then \: \\ k = \frac{48x {y}^{2} }{xy {}^{2} } \\ = 48$

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