Question

find the value of k if, y-1 is a factor of p(y)=ky^-3y+k​

Answer 1

Answer:

k=3/2

Step-by-step explanation:

y-1=0

y=1

p(1)=k(1)^-3(1)+k

=k-3+k

=2k-3

3=2k

k=3/2

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Answer 2

Answer:

HEY THERE , HERE IS YOUR ANSWER

P(y) = ky² -3y + k = 0

f(y) = y - 1 =0 ; y = 1

putting y =1 in give P(y) we get,

k(1)² - 3(1) + k = 0

k - 3 + k = 0

2k = 3

k =3/2

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