find the value of k if Y + 3 is a factor of 3 y square + K Y + 6
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Hlo
here is ur solution..
y + 3 = 0
y = -3
putting value :-
3y² + ky + 6 = 0
3 × ( -3 )² + k×-3 + 6 = 0
3 × 9 + ( -3 k ) + 6 = 0
27 - 3k + 6 = 0
33 - 3k = 0
-3k = -33
k = -33 / -3
k = 11
hope it helps..
here is ur solution..
y + 3 = 0
y = -3
putting value :-
3y² + ky + 6 = 0
3 × ( -3 )² + k×-3 + 6 = 0
3 × 9 + ( -3 k ) + 6 = 0
27 - 3k + 6 = 0
33 - 3k = 0
-3k = -33
k = -33 / -3
k = 11
hope it helps..
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