Question

Find the value of k , if y+3 is a factor of 3y (square)+ky+6

Answer 1

Answer:

$k=-11$

Step-by-step explanation:

According to the question,

Given,

$y+3$ is a factor of $3y^2+ky+6 = 0$

and the equation is $3y^2+ky+6 = 0$

So,

$y= -3$

when put $y= -3$

The equation becomes equal to zero

Now,

$3y^2+ky+6 = 0$

put y = -3

$3(-3)^2+3k+6 = 0\\27 + 3k + 6 = 0\\33 + 3k = 0\\3k = -33\\k = -11$

Hence, the value of k is equal to -11.

Answer 2

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