find the value of k , if y+3 is a factor of 3y2+3y2+kya+6
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(y+3)=0
y=-3
3y^2+3y^2+ky+6=0
6y^2+ky+6=0
6(-3)^2 + k(-3)+6=0
54+-18k=0
54=18k
k=3
y=-3
3y^2+3y^2+ky+6=0
6y^2+ky+6=0
6(-3)^2 + k(-3)+6=0
54+-18k=0
54=18k
k=3
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