Question

Find the value of k if y+3 is a factor of 3y2 + ky + 6​

Answer 1

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3y²+ky+6

y+3=0

y = -3

3y²+ky+6

3*[-3]²+k*-3+6=0

3*9-3k+6=0

27-3k+6=0

33-3k=0

k=-33/-3

k= 11

Answer 2

Answer:

11

Step-by-step explanation:

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