Question

find the value of K if y+3 is a factor of 3y2+ky +6​

Answer 1

Find K

 , if g(y) (y + 3) is a factor of p(y) 3y^2 + ky + 6. On verifying the above p(y) by putting the value of k as 11. Therefore , k = 11

hope this helps you

Answer 2

Answer:

p(x)=3y2+ky +6=0

p(-3)= 3$(-3)^{2}$+k(-3)+6=0

       27-3k+6=0

        33 -3k=0

            -3k= -33

               k= -33/-3= 11

∴ k=11

Step-by-step explanation: