Question

find the value of k if(y+3) is a factor of 3y² + ky +6​

Answer 1

QUESTION

$f(y) = 3y {}^{ 2 } + ky + 6 \\ \\ Given : y = 3 \\ \\ To \: find : k$

ANSWER:

$We \: know, \\ f(y) = f(3) = 0 \\ \\ f(3) = 3(3) {}^{2} + k(3) + 6 \\ \\ = > 27 + 3k + 6 = 0 \\ \\ = > 3k + 33 = 0 \\ \\ = > 3k = - 33 \\ \\ = > k = - 11$

Answer 2

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