Question

find the value of K, if y+3 is a factor of 3y²+ky+6. plz yar mera help kardo last question he​

Answer 1

Answer:

y-3 is factor of given eq.

y-3 =0

y= 3

putting value of y in given eq.

3(3×3) + k(3) +6 = 0

27 + 3k +6 = 0

33 + 3k = 0

3k = -33

k= -33/3

k = -11

Answer 2

I hope this will help you...

thanks