Question

Find the value of k, if zeroes of the polynomial kx^2−6x+9 are equal

Answer 1

Answer:

kkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk

Step-by-step explanation:

Answer 2

Answer:

k=1

Step-by-step explanation:

Let the two equal zeroes be p and p Let the given polynomial  be Kx2-6x+9 Sum of zeroes (p + p) = 6/k ⇒ 2p = 6/k ∴ p = 3/k Product of zeroes (p × p) = 9/k That is p2 = 9/k ⇒ (3/k)2 = 9/k ⇒ (3/k)2 –3(3/k) = 0 ⇒ (3/k)[(3/k) – 3]  = 0 3/k ≠ 0 Hence (3/k) – 3 = 0 (3/k) = 3 (1/k) =1 ∴ k = 1