Question

⚡Find the value of 'k'⚡

✨(ii) 3x² + 2kx – 3 = 0, x = 1✨​

Answer 1

$\huge{\boxed{\boxed{\red{\ulcorner{\mid{\overline{\underline{\bf{Answer:-}}}}}\mid}}}}$

$\huge \red \rightarrow \huge \red{k = 0.}$

A/Q,

$\red \rightarrow 3 {(1)}^{2} + 2k(1) - 3 = 0. \\ \\ \red \rightarrow \: \cancel3 + 2k - \cancel 3 = 0. \\ \\ \red \rightarrow \: 2k \: = 0. \\ \\ \red \rightarrow k = 0.$

$<marquee>Follow me$

$<marquee>Mark as Brainliest$

Answer 2

Solution :-

$p(1) = 3 ({1}^{2} ) + 2k(1) - 3 = 0 \\ \\ 3 + 2k - 3 = 0 \\ \\ 2k = 0 \\ \\ k = 0$