Math, asked by tictac1, 1 year ago

Find the value of k in 7x^2+kx-3=0 when x=2/3 is a solution of the equation

Answers

Answered by shrikant7
6
Hey here is your answer
Attachments:
Answered by Anonymous
9

Answer:

Given, x = 2/3

7x² + kx - 3 = 0

7.4/9 + 2/3k - 3 = 0

28/9 + (2k - 9)/3 = 0

(84 + 18k - 81)/27 = 0

84 + 18k - 81 = 0

3 + 18k = 0

1 + 6k = 0

6k = -1

k = -1/6 is the answer

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