Find the value of k in each of the following:
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i) (2/3)^3×(2/3)^6=(4/9)^(2k-3)
=> (2/3)^(3+6)=(2/3)^2(2k-3)
=> (2/3)^9=(2/3)^(4k-6)
4k-6=9
=> 4k=9+6
=> 4k=15
=> k=15/4
=> k=3 3/4
ii)
(-4/5)^2×(4/5)^5=(4/5)^(6k+1)
=> (-4/5)(-4/5)×(4/5)^5=(4/5)^(6k+1)
=> (4/5)^(5+2)=(4/5)^(6k+1)
=> 6k+1=7
=> 6k=7-1
=> 6k=6
=> k=6/6
=> k=1
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