Question

Find the value of k in
i) (2/3) ^ 3 * (2/3) ^ 6 = (4/9) ^ (2k - 3)
ii) (- 4/5) ^ 2 * (4/5) ^ 5 = (4/5) ^ (6k + 1) ​

Answer 1

Answer:

(i)15/4 (ii)-31503/125000

Step-by-step explanation:

(i) (2/3)^(3)×(2/3)^(6) = (4/9)^(2k-3)

(2/3)^(3+6) = {(2/3)²}^(2k-3)

(2/3)^(9) = (2/3)^(4k-6)

4k-6 = 9

4k = 9+6

4k = 15

k = 15/4

∴k =