Math, asked by kaynat87, 10 months ago

find the value of k in kx(x-2)+6=0

Answers

Answered by brainlygirl87
2

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Answered by gchandracommercial
6

Answer:

Given kx(x – 2) + 6 = 0

kx2 – 2kx + 6 = 0

Since the given quadratic equation has equal roots  we have b2 – 4ac = 0

That is (– 2k)2 – 4(k)(6) = 0

⇒ 4k2 – 24k = 0

⇒ 4k(k – 6) = 0

⇒ 4k = 0 or (k – 6) = 0

∴ k = 0 or 6

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