Question

Find the value of k in kx²-36=(5x+6)(5x-6)

Answer 1

Answer:

LHS:KX^2

RHS:(5X+6)(5X-6)

SOLVING RHS USING:

IDENTITY( a+b) (a-b)=a^2-b^2

=(5x+6)(5x-6)=(5x)^2-6^2=25x^2-36

So value of k is 25.

Answer 2

Answer:

25

Step-by-step explanation:

kx2-36=(5x+6)(5x-6)

kx2-36=25x2-36

25x2-36+36-kx2=0

x2(25-k)=0

25-k=O

k=25