Question

find the value of k in limx-5 x^k-5^k/x-5=500

Answer 1

Answer:

Lim(x->a) [x^k - a^k/x-a] = k.a^(k-1)

So in above eqn : a = 5

So k.5^(k-1) = 500 = 4×125 = 4×5^(4-1)

So k = 4

Pls mark Brainliest and Follow me for more answers.