Question

find the value of k in p (x)=x2+11x+k if -4 is a zero p (x).

Answer 1

$( - 4) {}^{2} + 11 \times ( - 4) + k = 0 \\ 16 - 44 + k = 0 \\ k = 28$

Answer 2

Hi friend
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Your answer
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p(x) = x² + 11x + k

(-4) is a zero of the given polynomial.

so,
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p(-4) = (-4)² + 11×(-4) + k = 0

16 - 44 + k = 0

-28+ k = 0

k = 28

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