Question

Find the value of k in quadrant eqñ 3x-k✓3x-4=0 has equal root

Answer 1

$b {}^{2} - 4ac = 0$
$(k \sqrt{3} ) {}^{2} - 4(3 )\times - 4 = 0 \\ k {}^{2} 3 + 24 = 0 \\ k {}^{2} 3 = - 24 \\ k { }^{2} = - 8 \\ k = - 4 \sqrt{2}$
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