Question

find the value of K, in quadratic equation 9x²-Kx+16=0.if roots are equal.​

Answer 1

Answer:

k=24

Step-by-step explanation:

roots are equal then b^2-4ac=0

here b=-k, a=9, c=16

substitute a,b,c values in descriminent

(-k)^2-4(9)(16)=0

k^2=36×16

k=6×4

k=24

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Answer 2

Answer:

k=±24

Step-by-step explanation:

9x²-Kx+16=0

Here a=9,b=-k c=16

If the roots are equal then

b²=4ac

k²=4*9*16

k=√4*9*16

=±2*3*4 = ±24