Question

find the value of k in quartic equation 9xsquare-kx+16 =0​

Answer 1

Answer:

The value of determinant should be zero.

i.e. D=b²-4ac=0———(1)

Where in this case,

b=8k

a=9 , and

c=16

Substituting the above values in (1)

=>64k²-4*9*16=0

=>64k²-576=0

=>64k²=576

=>k²=576/64

=>k²=9

=>k=+3 or -3

Hence , for the equation nto have equal roots the value of k is either +3 or -3

Step-by-step explanation:

Answer 2

Answer:

k is +3/-3.......

hope it helps