Question

find the value of k in th QE which have equal roots kx^2+2(k-4)x+2=0​

Answer 1

Answer:

here is your answer

Step-by-step explanation:

The given quadratic equation is :

kx

2

+4x+1=0

Here, a=k,b=4,c=1

Now, D=b

2

−4ac=(4)

2

−4×k×1=16−4k

We know that a quadratic equation has real and equal roots

If D=0

⇒16−4k=0

⇒−4k=−19

∴k=

−4

−16

=4

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