Find the value of k in the equation 2kx^2 - 20x+21 when one of its roots exceeds the other by 2
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x=2
p(2)=2k(2)^2-20×2+21=0
=8k-40+21=0
=8k=19
=k=19\8
p(2)=2k(2)^2-20×2+21=0
=8k-40+21=0
=8k=19
=k=19\8
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