Find the value of k in the following:
(2/3) ^ 3 * (2/3) ^ 6 = (4/9) ^ (2k - 3)
Please answer with explanation its urgent.This question is of class 7th.
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Answer:
Since these terms are consecutive terms of an A.P., the middle term must be the average of the other two.
⇒(k−3)+(4k+3)=2(2k+1)
⇒5k=4k+2
⇒k=2
Thus, the required value of k is 2.
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