Question

find the value of k in the following polynomials for which the indicated values of x are their zeros 9x²+8kx+16 (x=4/3)​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

BY PUTTING VALUE LIKE THIS

9*(4/3)*2+8*4/3*K+16=0

9*16/9+32K/3+16=0

16+32K/3+16=0

(16*3+32k+16*3)/3=0

(48+32k+48)/3=0

(96+32k)/3=0

96+32k=0*3

96+32k=0(because if we multiply any number with 0 its product is always 0)

32k= -96

k= -96/32

k= -3