Question

find the value of k in the following quadratic equation
(k+1)x^2 - 2(k+4)x + 2k = 0​

Answer 1

Answer:

2

D=b -4ac

0=(2(k+4))^2-4(k+1)(2k)

0=(4(k2+16+8k) -4(2k^2+2k)

0=k^2+16+8k-2k^2+2k

0=-k^2+16+20k

k^2=16+20k

k=36

k=6

Answer 2

here is your answer..............