Question

find the value of k in the given equation
$k{x }^{2} - 3 \sqrt{2} x + 4 \sqrt{2} = 0$
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Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Answer:

Given Equation: 2x² + kx +3

It is said that the above equation has real and equal roots.

Therefore we can say that the value of the discriminant is equal to 0.

b²-4ac=0

According to the question, a = 2, b=k, c = 3

Therefore on substituting we get.

k²-4 (2) (3) = 0

⇒ k²-24-0

→ K² = 24

→ k = √24 = ±2√6

Therefore the value of k is ± 2√6.

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