Math, asked by tanya191, 7 months ago


Find the value of K in the number 5K3457
when it is divisible by 11

Answers

Answered by saikethan24
5

Step-by-step explanation:

If a number is divisible by 11, then sum of even places of number= sum of odd places

so, number= 5k3457

even places of number= k,4,7

odd places of number= 5,3,5

sum of odd places= sum of even places

so, k+4+7= 5+3+5

11+k= 13

k= 13-11=2

so, k=2

Answered by swanandgunjal
3

Answer:

5

Step-by-step explanation:

if k = 5

5 + 5 + 3 + 4 + 5 + 7 = 29

2 + 9 = 11 when the sum of all no. is divisible by 11 . then all no. is divisible by 11...

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