Question

find the value of k in the quadratic equation 9 x square -k s x + 16 is equal to zero if roots are equal​

Answer 1

Answer :-

→ K = 16

To Find:-

→ Value of K .

Explanation :-

We have ;

→ 9x² - 24x + k = 0

According to the question its roots are real and equal .

We know that if roots of any quadratic polynomial are equal so it's discriminate will zero.

If we have a quadratic equation

→ ax² + bx + c = 0. eq.(1)

then , it's discriminate D is

→ D = b² - 4ac

Compare the given equation with eq.(1)

→ a = 9 , b = -24 and c = k

therefore , it's discriminate is

hence K = 16 .

Now we have our quadratic equation .

→ 9x² - 24x + 16 = 0

Its discriminate is 0 ,so its roots are real and equal.

Answer 2

Answer:

sorry but I can't understand ur point