Question

find the value of K in which one it's zeroes is -4 9f the polynomial p (x) = x2-x-(2k+2)​

Answer 1

Answer:

x = - 4 is the zero of the polynomial

Substituting,

P(-4) = (-4)² - (-4) - (2k + 2) = 0

8 + 4 - 2k - 2 = 0

10 - 2k = 0

2k = 10

k = 10/2

k = 5

Value of k is 5

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