Math, asked by sudheerbabu17, 9 months ago

find the value of K, in which one its
Zeroes is -4 of the polynomial P(x)^2-x
(2k + 2)

Answers

Answered by Anonymous

3

Answer:

-4^2 - [ -4 ( 2k + 2 ) ]

16 - ( - 8k - 8 )

16 + 8k + 8

24 + 8k

8k = -24

k = -3

hope it helps you

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