find the value of k in x^2 - 4x+k=0 has coincident roots
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Answered by
11
Answer: k should be equal to 4
Step-by-step explanation:
Since it is a quadratic equation so Drisminiant must be equal to 0
So, D=0
b^2-4ac = 0
Putting the values a=1 b=4 c=k
We get
4^2-4×1×k = 0
16= 4k
k=16÷4= 4
Therefore, k must be equal to 4
Answered by
3
Answer:
the answer is k=4
Step-by-step explanation:
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