Question

Find the value of k, infinitely many solutions  2x+3y=7,(k+1)x+(k+2)y=3k​

Answer 1

Answer:

1 is the answer I think k sorrry

Answer 2

Answer:

For infinitely many solutions ,

Condition -->

$\frac{a1}{a2} = \frac{b1}{b2} = \frac{c1}{c2}$

Step-by-step explanation:

So , a1=2

a2=(k+1)

b1=3

b2=(k+2)

c1= -7

c2= -3k

So , B T P

$\frac{2}{k + 1} = \frac{3}{k + 2}$

$= > 2(k + 2) = 3(k + 1)$

$= > 2k + 4 = 3k + 3$

$= > k = 1$

....................(1)

Also ,

$\frac{3}{k + 2} = \frac{ - 7}{ - 3k}$

$= > 3 \times 3k = 7(k + 2)$

$= > 9k = 7k + 14$

$= > 2k = 14$

$= > k = 7$

.....................(2)

So , k will have any two values . 1 or 7 . [ Answer ]

Hope this helps you.