Question

find the value of k is x-1 the factor of the following
$p(x) = {2x}^{2} + kx + \sqrt{2}$

Answer 1

Hey user here is your answer.........


------>x-1=0
------>x=1

So,
put this in given equation

p(1)=2(1)^2+k(1)+root2

p(1)=2+k+root2
k+root2=-2
k=
$- \sqrt{2} - 2$
$- ( \sqrt{2 } + 2)$
Thanks☺️