Question

Find the value of k (k-2)x2 + 2(2k-3)x + (5k-6) has equal roots

Answer 1

Solñ: (k-2)x²+2(2k-3)x+(5k-6)

Here,

a=k-2. b=2(2k-3)=4k-6 c=5k-6

Given the equation has equal roots=0

So, b²-4ac=0

»[4k-6]²-4.(k-2).(4k-6)=0

»16k²-2.4k.6+6²-4(16k²-6k-8k+6k)=0

»16k²-48k+36-64k²-56k+24k=0

»-48k²-104k+24k=0

»-8k(6k+13-3)=0

»6k+10=0

»6k=-10

»k=-10/6

=-5/3

The value of k=-5/3