Find the value of k ,k x square - 3x-k =0 , x=-1÷2
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Hey there !
Here is your solution:
kx² - 3x - k = 0 where x = -1/2
So, k(-1/2)² -3(-1/2) - k = 0
=> k/4 + 3/2 - k = 0
=> (k + 6 - 4k)/4 = 0 [Taking LCM]
=> k + 6 - 4k = 0
=> -3k = -6
=> k = 2
Hope this helps ya ✌️
Here is your solution:
kx² - 3x - k = 0 where x = -1/2
So, k(-1/2)² -3(-1/2) - k = 0
=> k/4 + 3/2 - k = 0
=> (k + 6 - 4k)/4 = 0 [Taking LCM]
=> k + 6 - 4k = 0
=> -3k = -6
=> k = 2
Hope this helps ya ✌️
eminemrules101:
Lol, Roshni hai bhai
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