Question

Find the value of k .kc^2-2kx+6=0

Answer 1

Answer:

k = 6

Step-by-step explanation:

For equal roots,

b^2 - 4ac = 0

Here, p(x) = kx^2 - 2kx + 6

a = k , b = -2k , c = 6

b^2 - 4ac = 0

(-2k)^2 - 4(k)(6) = 0

4k^2 - 24k = 0

k(4k - 24) = 0

4k - 24 = 0

4k = 24

k = 24/4

k = 6

Answer 2

Step-by-step explanation:

put x=c=1

k(1)2-2k(1)+6=0

k-2k+6=0

-k+6=0

k=6