Question

find the value of k. kx+3y=5, 3y-4y=10​

Answer 1

Answer:

Given equations are

kx+3y=5 __(1)

3y-4y=10 → y= -10 __(2)

Substitute (2) in (1)

Then,

k= 35/x

Answer 2

Answer:

hi mate ,

Step-by-step explanation:

. System of equation kx+2y=5 and 3x−4y=10

Here,

. a1 = k , b1 = 2 , c1 = 5

. a2 = 3 , b2 = -4 , c2 = 10          

. a1 /a2 = k/3 , b1 /b2 = 2 /-4  = -1/2

. c1 /c2 = 5 / 10 = 1/2

. System has a unique solution.

. a1 /a2 ≠ b1 / b2 ⇒ k/3 ≠ -1 / 2

. k ≠ -3/2

(note : pls see all the steps and ur value of kx + 3y =5 should be not 3y it is 2y )

thank you