Question

find the value of k, kx(x_2)+6=0​

Answer 1

Answer:

kx(x-2)+6=0

kx^2-2kx+6=0

Since the given quadratic equation has equal roots we have b^2-4ac=0

that is (-2k)2-4(k)(6)=0

4k^2-24k=0

4k(k-6)=0

4k=0 or (k-6)=0

k=0 or k=6

⬆️hope it helps you✔

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