find the value of k linear pair x+y-4=o and 2x+ky-3=0 have no soulution
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Answer:
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Step-by-step explanation:
a1/a2=b1/b2
1/2=1/k
k=2
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5
Given :-
▪ Two Linear equations in two variables,
- x + y - 4 = 0
- 2x + ky - 3 = 0
To Find :-
▪ Value of k for which the system of equations will have no solution.
Solution :-
Given us two linear equations in two variables, So let us find the coefficients of the variables of both the equations by comparing with the standard form of a linear equation in two variables i.e., ax + by + c = 0
- a₁ = 1 ; b₁ = 1 ; c₁ = -4
- a₂ = 2 ; b₂ = k ; c₂ = -3
For a system of equations to have no solution, the coefficients follow the given condition
⇒ a₁ / a₂ = b₁ / b₂ ≠ c₁ / c₂
First, Solving the first condition , a₁ / a₂ = b₁ / b₂
⇒ 1 / 2 = 1 / k
⇒ k = 2
Now, the second condition, b₁ / b₂ ≠ c₁ / c₂
⇒ 1 / k ≠ -4 / -3
⇒ 1 / k ≠ 4 / 3
⇒ k ≠ 3 / 4
So, The value of k is 2.
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