Find the value of k of 2x 3y-5=0,kx-6y-8=0 by the method for unique solutions
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Hey! Here is ur answer...
2x+3y= 5 and kx-6y = 8
Unique Solution Case-
a1/a2 # b1/b2
So, 2x/kx # 3y/-6y
2/k # -1/2
4 # -k
k # -4
I Have Used # SymbolTo Symbolise Unequally!
Hence The Equation Will Have Unique Solution When k # -4
Hope it helps u... Plz mark it as brainliest... :)
2x+3y= 5 and kx-6y = 8
Unique Solution Case-
a1/a2 # b1/b2
So, 2x/kx # 3y/-6y
2/k # -1/2
4 # -k
k # -4
I Have Used # SymbolTo Symbolise Unequally!
Hence The Equation Will Have Unique Solution When k # -4
Hope it helps u... Plz mark it as brainliest... :)
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