Question

find the value of k of 9x²+6kx+4=0,when roots are equal

Answer 1

Here is your answer ! ! ! ! !


when roots are equal =》b^2 - 4ac = 0
( 6k )^2 - 4 ( 9) ( 4) = 0
36 k^2 - 144 = 0
36 k^2 = 144
k^2 = 144 ÷ 36
k^2 = 4
k = 2

So the value of k is 2



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Answer 2

SOLUTION :  

Option (a) is correct : ± 2/3

Given : 9x² + 6kx + 4 = 0 …………(1)

On comparing the given equation with ax² + bx + c = 0  

Here, a = 9 , b = 6k , c = 4

D(discriminant) = b² – 4ac

D = (6k)² - 4 × 9 × 4

D = 36k² -  144

Given equation has equal roots , i e D = 0

36k² -  144 = 0

36(k² - 4) = 0

k² - 4 = 0

k² = 4

k = √4

k = ± 2

On putting k =  2 in eq 1,

9x² + 6(2)x + 4 = 0

9x² + 12x + 4 = 0  

Here, a = 9 , b =  12 , c = 4  

D = b² - 4ac  

D = (12)² - 4 × 9 × 4

D = 144 - 144

D = 0

When D = 0 , then x = - b/2a , x = - b/2a

x = - 12/(2×9)

x = - 12/18 = - ⅔

x = - ⅔  

On putting k = -  2 in eq 1,

9x² + 6(-2)x + 4 = 0

9x² - 12x + 4 = 0  

Here, a = 9 , b =  - 12 , c = 4  

D = b² - 4ac  

D = (-12)² - 4 × 9 × 4

D = 144 - 144

D = 0

When D = 0 , then x = - b/2a , x = - b/2a

x = -(- 12)/(2×9)

x = 12/18 = ⅔

x = ⅔  

Hence, the roots are x = ± ⅔ .

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