Question

Find the value of K' of Q.E 2x*- kx +2 = 0 if they have two equal roots.
help me​

Answer 1

Answer:

2x2+kx+3=0   ---(1)

if eq (1)has equal roots then

Discriminant (1)=b2−4ac=0

b2=4ac

k2=4×2×3

k2=24

k=24=±26

∴ for k = ±216 given equation has equal roots.

Answer 2

Explanation:

k= 126

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