Question

Find the value of k of the difference of their roots x^2-5x+3(k-1)=0 is 11

Answer 1

Answer:

Step-by-step explanation:

a+b=5

ab=3(k-1)

squaring on both sides

a^2+b^2+2ab=25

a^2+b^2+2(3(k-1))=25

a^2+b^2=25-6k+6=31-6k

(a-b)=11

a^2+b^2-2ab=121

31-6k-2(3(k-1))=121

31-6k-6k+6=121

-12k=121-37

-12k=84

k=-7