Question

find the value of k of the equation 5x-4y+1=0 and 7k+6y-9=0 is consistent solution

Answer 1

Step-by-step explanation:

let k=x

5x-4y+1=0. 1

7x+6y-9=0. 2

multiply equation 1 by 7

and 2 by 5 so we get

35x-28y+5=0. 3

35x+30y-45=0. 4

by subtracting equ 1 and 2 we get

-58y+50=0

-58y=-50

y=-50/-58

y=25/29

put it in 1 we get

5x-4(25/29)+1=0

5x-100/29+1=0

5x=100/29-1

5x=100-29/29

5x=71/29

x=71/29*5

x=71/145

as x=k so

k=71/145