Find the value of k of the give quadratic equation whose roots are real and equal :- 2x^-(k - 1 )x+8
Answers
Answered by
1
Answer:
Step-by-step explanation:2x^2-(k-1)x+8=0
By using b^2-4ac=0
Given roots are real and equal
So
b^2-4ac=0
(-(k-1))^2-4(2)(8)=0
(-k+1)^2-4(2)(8)=0
K+1-2k-64=0
-k-63=0
K=-63
Answered by
0
Answer:
2xsquare-(k-1)x+8
compare with ax2+bx+c=0
a=1b=-k+1c=8
√bsquare-4ac
√-k+1square -4*1*8
√k+1-32=0
k=√31
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