Question

Find the value of k of the give quadratic equation whose roots are real and equal :- 2x^-(k - 1 )x+8​

Answer 1

Answer:

Step-by-step explanation:2x^2-(k-1)x+8=0

By using b^2-4ac=0

Given roots are real and equal

So

b^2-4ac=0

(-(k-1))^2-4(2)(8)=0

(-k+1)^2-4(2)(8)=0

K+1-2k-64=0

-k-63=0

K=-63

Answer 2

Answer:

2xsquare-(k-1)x+8

compare with ax2+bx+c=0

a=1b=-k+1c=8

√bsquare-4ac

√-k+1square -4*1*8

√k+1-32=0

k=√31