find the value of k of the quadratic equation kx (x-2)+6=0 which have two equal roots
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Answer:
k = 6
Step-by-step explanation:
Q.E = kx (x - 2) + 6 = 0
⇒ kx² - 2kx + 6 = 0
a = k , b = -2k , c = 6
If the equation has two equal roots then D = 0
⇒ b² - 4ac = 0
⇒ (-2k)² - 4(k)(6) = 0
⇒ 4k² - 24k = 0
⇒ 4k(k - 6) = 0
⇒ k = 0 , k = 6
On sub. k = 0 the equation does not give quadratic equation.
∴ k = 6
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