Question

Find the value of K, of the roots of the quadratic equation 3y2

+ ky + 12 = 0 are real

and equal.​

Answer 1

Step-by-step explanation:

3y²+ ky + 12 = 0

3y²+ky=0-12

y²+ky=-12/3

ky=-4-y²

k=-4-y²-y

k=-4-2y²