find the value of K of x+3 is a factor of 3x²+kx+6
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Since, (x+3) is a factor of 3x²+kx+6,
So, -3 is the zero of the above polynomial.
Now, putting the value of x as -3,
=》3(-3²)+k(-3)+6=0
=》3(9)-3k+6=0
=》27+6=3k
=》33=3k
=》k=33/3
=》k=11
So, k=11
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hope it's right . pls comment if it's right or wrong
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